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A cell contains two hydrogen electrodes....

A cell contains two hydrogen electrodes. The negative electrode is in contact with a solution of `10^(-6)M` hydrogen ions. The `EMF` of the cell is `0.118V` at `25^(@)C`. Calculate the concentration of hydrogen ions at the positive electrode.

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The correct Answer is:
`10^(2) xx 10^(-6)=10^(-4)M`
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