A Daniel cell produces a current of 3.6mA at 1.1 V for 15 minutes. What is the maximum possible work you can get from it?

Answer

To find the maximum possible work that can be obtained from a Daniel cell producing a current of 3.6 mA at 1.1 V for 15 minutes, we can follow these steps:

### Step-by-Step Solution:

1. **Convert Current to Amperes**:
- The given current is 3.6 mA. To convert this to amperes:
\[ I = 3.6 \, \text{mA} = 3.6 \times 10^{-3} \, \text{A} \]

2. **Convert Time to Seconds**:
- The given time is 15 minutes. To convert this to seconds:
\[ T = 15 \, \text{minutes} \times 60 \, \text{seconds/minute} = 900 \, \text{seconds} \]

3. **Calculate the Work Done**:
- The work done (W) can be calculated using the formula:
\[ W = V \times Q \]
- Where \( Q \) (the charge) is given by:
\[ Q = I \times T \]
- Substituting the values:
\[ Q = (3.6 \times 10^{-3} \, \text{A}) \times (900 \, \text{s}) = 3.24 \, \text{C} \]

4. **Substituting into the Work Done Formula**:
- Now substituting \( Q \) into the work done formula:
\[ W = V \times Q = 1.1 \, \text{V} \times 3.24 \, \text{C} = 3.564 \, \text{J} \]

5. **Final Answer**:
- The maximum possible work that can be obtained from the Daniel cell is:
\[ W \approx 3.564 \, \text{J} \]