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In a Galvanic cell involving the redox r...

In a Galvanic cell involving the redox reaction:
`A^(2+)+ B_((s)) Leftrightarrow A_((s))+B^(2+)`
The `E_("cell")` will not be equal to `E_("cell")^(0)` when

A

`[A^(2+)]=[B^(2+]=1M`

B

`[A^(2+)]=[B^(2+)]=0.1M`

C

`[A^(2+)]=[B^(2+)]=0.5M`

D

None of the above

Text Solution

AI Generated Solution

The correct Answer is:
To determine when the cell potential \( E_{\text{cell}} \) will not be equal to the standard cell potential \( E_{\text{cell}}^{0} \) for the given redox reaction: \[ A^{2+} + B_{(s)} \leftrightarrow A_{(s)} + B^{2+} \] we will analyze the conditions under which the Nernst equation applies. ### Step 1: Write the Nernst Equation The Nernst equation relates the cell potential \( E_{\text{cell}} \) to the standard cell potential \( E_{\text{cell}}^{0} \) and the reaction quotient \( Q \): \[ E_{\text{cell}} = E_{\text{cell}}^{0} - \frac{0.0591}{n} \log Q \] where \( n \) is the number of moles of electrons transferred in the redox reaction. ### Step 2: Identify the Reaction Quotient \( Q \) For the given reaction, the reaction quotient \( Q \) is defined as: \[ Q = \frac{[B^{2+}]}{[A^{2+}]} \] ### Step 3: Determine the Value of \( Q \) The values of \( [A^{2+}] \) and \( [B^{2+}] \) will affect \( Q \). If both concentrations are equal, \( Q \) will equal 1, and the logarithm of 1 is 0. ### Step 4: Analyze Each Condition 1. **Condition 1: \( [A^{2+}] = [B^{2+}] = 1 \, \text{M} \)** - Here, \( Q = \frac{1}{1} = 1 \) - Thus, \( E_{\text{cell}} = E_{\text{cell}}^{0} - \frac{0.0591}{n} \cdot 0 = E_{\text{cell}}^{0} \) 2. **Condition 2: \( [A^{2+}] = [B^{2+}] = 0.1 \, \text{M} \)** - Again, \( Q = \frac{0.1}{0.1} = 1 \) - Thus, \( E_{\text{cell}} = E_{\text{cell}}^{0} - \frac{0.0591}{n} \cdot 0 = E_{\text{cell}}^{0} \) 3. **Condition 3: \( [A^{2+}] = [B^{2+}] = 0.5 \, \text{M} \)** - Similarly, \( Q = \frac{0.5}{0.5} = 1 \) - Thus, \( E_{\text{cell}} = E_{\text{cell}}^{0} - \frac{0.0591}{n} \cdot 0 = E_{\text{cell}}^{0} \) ### Conclusion In all three conditions, \( E_{\text{cell}} \) is equal to \( E_{\text{cell}}^{0} \). Therefore, the correct answer to the question is: **None of these**
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