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Given Fe^(2+)+2e^(-) Leftrightarrow Fe "...

Given `Fe^(2+)+2e^(-) Leftrightarrow Fe " "E^(0)=-0.44V`
`Co^(2+)+2e^(-) Leftrightarrow Co" "E^(0)=0.28V`
`Ca^(2+)+2e^(-) Leftrightarrow Ca" "E^(0)=-2.87V`
`Cu^(2+)+2e^(-) Leftrightarrow E^(0)=+0.337V`
Which is tha most electropositive metal?.

A

Fe

B

Co

C

Ca

D

Cu

Text Solution

AI Generated Solution

The correct Answer is:
To determine which is the most electropositive metal among the given options, we need to analyze the standard reduction potentials (E°) provided for each metal. The electropositivity of a metal is related to its ability to lose electrons and form positive ions. A more negative standard reduction potential indicates a greater tendency to lose electrons, thus making the metal more electropositive. ### Step-by-Step Solution: 1. **Identify the Standard Reduction Potentials**: - For Fe²⁺ + 2e⁻ ↔ Fe, E° = -0.44 V - For Co²⁺ + 2e⁻ ↔ Co, E° = +0.28 V - For Ca²⁺ + 2e⁻ ↔ Ca, E° = -2.87 V - For Cu²⁺ + 2e⁻ ↔ Cu, E° = +0.337 V 2. **Convert to Standard Oxidation Potentials**: - The standard oxidation potential can be calculated by changing the sign of the standard reduction potential: - For Fe: E° (oxidation) = +0.44 V - For Co: E° (oxidation) = -0.28 V - For Ca: E° (oxidation) = +2.87 V - For Cu: E° (oxidation) = -0.337 V 3. **Compare the Oxidation Potentials**: - Fe: +0.44 V - Co: -0.28 V - Ca: +2.87 V - Cu: -0.337 V 4. **Identify the Most Electropositive Metal**: - The metal with the highest oxidation potential is the most electropositive. From the values calculated: - Ca has the highest oxidation potential of +2.87 V. 5. **Conclusion**: - Therefore, the most electropositive metal among the given options is **Calcium (Ca)**.
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