Home
Class 12
CHEMISTRY
For a solution if p(A)^(@)=600" mm Hg",p...

For a solution if `p_(A)^(@)=600" mm Hg",p_(B)^(@)=840" mm Hg"` under atmospheric conditions and vapour pressure of solution is 1 atm then find
(i) Composition of solution
(ii) Composition of vapour in equilibrium wiht solution

A

`CaCN_(2)` (nitrolim)

B

`Li_(3)N`

C

`Mg_(3)N_(2)`

D

all of the above

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Liquids A (p_(A)^(@)=360" mm Hg") and B(p_(B)^(@)=320" mm Hg") are mixed. If solution has vapour pressure 340 mm Hg, then mole fraction of B will be

Liquids A (p_(A)^(@)=360" mm Hg") and B(p_(B)^(@)=320" mm Hg") are mixed. If solution has vapour has vapour pressure 340 mm Hg, then number of mole fraction of B/mole solution will be

V.P. of solvent in pure state is 600 mm Hg, when a non-volatile solute is added to it vapour pressure of solution becomes 594 mm Hg, then x_(B) will be

Benzene and toluene form nearly ideal solution. If at 300K P_("bentezne")=103.01 mm. (i) Calculate the vapour pressure of a solution containing 0.6 mole fraction of toluene. (ii) Calculate the mole fraction of toluene in the vapour form for this composition of liquid.

Vapour pressure of CH_(3)Cl and CH_(2)Cl_(2) are 540 mm Hg and 402 mm Hg respectively. 101 g of CH_(3)Cl and 85 g of CH_(2)Cl_(2) are mixed together. Determine (i) The pressure at which the solution starts boiling. (ii) Molar ratio of solute v/s solvent in vapour phase in equilibrium with solution.

Vapour pressure of CH_(3)Cl and CH_(2)Cl_(2) are 540 mm Hg and 402 mm Hg respectively. 101 g of CH_(3)Cl and 85 g of CH_(2)Cl_(2) are mixed together. Determine (i) The pressure at which the solution starts boiling. (ii) Molar ratio of solute v/s solvent in vapour phase in equilibrium with solution.

Vapour pressure of pure water is 40 mm. if a non-volatile solute is added to it, vapour pressure falls by 4 mm. Hence, molality of solution is

The vapour pressure of pure benzene at 25^@C is 640 mm Hg and that of the solute A in benzene is 630 mm of Hg. The molality of solution of

The total vapour pressure of equimolar solution of benzene and toluene is given by P_(T) (in mm Hg) =600-400X_("toluene") then:

Vapour pressure of pure A(p_(A)^(@))=100 mm Hg Vapour pressure of pure B(p_(B)^(@))= 150 mm Hg 2 mol of liquid A and 3 mol of liquid B are mixed to form an ideal solution. The vapour pressure of solution will be: