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{:(BaC(2) + N(2) overset(Delta)rarr (A))...

`{:(BaC_(2) + N_(2) overset(Delta)rarr (A)),(CaC_(2) + N_(2) overset(Delta)rarr (B)):}`
(A) and (B) are

A

`BaCN_(2), CaCN_(2)`

B

`Ba(CN)_(2), Ca (CN)_(2)`

C

`Ba(CN)_(2), CaCN_(2)`

D

none of the above

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the reactions of barium carbide (BaC₂) and calcium carbide (CaC₂) with nitrogen gas (N₂) upon heating, we will follow these steps: ### Step 1: Identify the Reactants The reactants given in the question are: - Barium carbide (BaC₂) - Calcium carbide (CaC₂) - Nitrogen gas (N₂) ### Step 2: Write the Reaction for Barium Carbide When barium carbide (BaC₂) reacts with nitrogen gas (N₂) upon heating, the expected product is barium cyanide (Ba(CN)₂). The balanced reaction can be written as: \[ \text{BaC}_2 + \text{N}_2 \overset{\Delta}{\rightarrow} \text{Ba(CN)}_2 \] ### Step 3: Write the Reaction for Calcium Carbide Similarly, when calcium carbide (CaC₂) reacts with nitrogen gas (N₂) upon heating, the expected product is calcium cyanide (Ca(CN)₂). The balanced reaction can be written as: \[ \text{CaC}_2 + \text{N}_2 \overset{\Delta}{\rightarrow} \text{Ca(CN)}_2 \] ### Step 4: Identify the Products From the reactions: - Product A from the reaction of BaC₂ is barium cyanide, represented as Ba(CN)₂. - Product B from the reaction of CaC₂ is calcium cyanide, represented as Ca(CN)₂. ### Final Answer Thus, the final products are: - (A) = Ba(CN)₂ (Barium cyanide) - (B) = Ca(CN)₂ (Calcium cyanide) ---
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