When `Cl_(2)` is passed into moist slaked lime, compound formed is

Options

A. `CaO_(2)Cl_(2)`
B. `CaO_(2)Cl`
C. `CaOCl_(2)`
D. `CaCl_(2)O_(4)`

Answer

To solve the question of what compound is formed when chlorine gas (Cl₂) is passed into moist slaked lime, we can follow these steps:

### Step 1: Identify the reactants
The reactants in this reaction are chlorine gas (Cl₂) and moist slaked lime. Slaked lime is chemically represented as calcium hydroxide (Ca(OH)₂).

### Step 2: Write the chemical formula for moist slaked lime
Moist slaked lime can be represented as a mixture of calcium oxide (CaO) and water (H₂O) or simply as calcium hydroxide (Ca(OH)₂).

### Step 3: Write the reaction
When Cl₂ is passed through moist slaked lime (Ca(OH)₂), a chemical reaction occurs. The reaction can be represented as follows:

\[ \text{Cl}_2 + \text{Ca(OH)}_2 \rightarrow \text{Ca(OCl)}_2 + \text{H}_2\text{O} \]

### Step 4: Identify the product
The product formed in this reaction is calcium oxychloride, which can also be represented as calcium hypochlorite (Ca(OCl)₂).

### Step 5: Conclusion
Thus, the compound formed when Cl₂ is passed into moist slaked lime is calcium oxychloride (Ca(OCl)₂).

### Final Answer
The compound formed is Ca(OCl)₂.

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