The following acids have been arranged in order of increasing acid strength. Identify the correct order.
CIOH (I) BOrH (1) IOH (III) 

Options

A. Iltllltlll
B. IIltlltlll
C. III ltIlltI
D. Iltlll ltIl

Explanation

To determine the correct order of increasing acid strength for the given acids (CIOH, BOrH, IOH), we need to consider the electronegativity of the halogens attached to the hydroxyl group (-OH). The more electronegative the element, the stronger the acid, as it stabilizes the negative charge on the conjugate base after the acid donates a proton (H⁺).

### Step-by-Step Solution:

1. **Identify the Acids and Their Components:**
- CIOH (Hypochlorous acid)
- BOrH (Hypobromous acid)
- IOH (Hypoiodous acid)

2. **Determine the Electronegativity of the Halogens:**
- Chlorine (Cl) has the highest electronegativity among the three.
- Bromine (Br) is less electronegative than chlorine.
- Iodine (I) has the lowest electronegativity.

The order of electronegativity is: Cl > Br > I.

3. **Analyze Acid Strength Based on Electronegativity:**
- The strength of an acid increases with the electronegativity of the atom bonded to the hydroxyl group because a more electronegative atom can better stabilize the negative charge on the conjugate base after the acid donates a proton.
- Therefore, CIOH (Cl) will be the strongest acid, followed by BOrH (Br), and then IOH (I) as the weakest acid.

4. **Arrange the Acids in Order of Increasing Acid Strength:**
- The order from weakest to strongest acid is:
- IOH (weakest)
- BOrH
- CIOH (strongest)

5. **Final Order of Increasing Acid Strength:**
- The correct order of increasing acid strength is:
- IOH < BOrH < CIOH

### Conclusion:
The correct order of increasing acid strength is:
**IOH < BOrH < CIOH**