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Consider the equilibrium equation, CH(3)...

Consider the equilibrium equation, `CH_(3)COOH+HI leftrightarrowCH_(3)COOH_(2)^(+) + I^(-) ` which of the following statements is/are incorrect?

A

`I^(-)` is the conjugate base of HI.

B

`I^(-)`is the conjugate base of `CH_(3)COOH`

C

`CH_(3)COOH`, is the conjugate acid of `CH_(3)COOH`

D

`CH_(3)COOH`, is the conjugate acid of `CH_(3)COOH_(2)^(+)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the equilibrium equation `CH₃COOH + HI ⇌ CH₃COOH₂⁺ + I⁻`, we need to analyze the statements provided and determine which ones are incorrect. ### Step-by-Step Solution: 1. **Identify the Acid and Base in the Reaction:** - In the reaction, `CH₃COOH` (acetic acid) donates a proton (H⁺) to form `CH₃COOH₂⁺` (the conjugate acid). - `HI` (hydroiodic acid) also donates a proton to form `I⁻` (iodide ion). 2. **Determine the Conjugate Bases and Acids:** - The conjugate base of an acid is what remains after the acid donates a proton. - For `HI`, when it donates a proton, it forms `I⁻`, so `I⁻` is the conjugate base of `HI`. - For `CH₃COOH`, when it donates a proton, it forms `CH₃COOH₂⁺`, so `CH₃COOH₂⁺` is the conjugate acid of `CH₃COOH`. 3. **Analyze Each Statement:** - **Option 1:** `I⁻ is the conjugate base of HI.` - This statement is **correct** because `I⁻` is formed when `HI` donates a proton. - **Option 2:** `I⁻ is the conjugate base of CH₃COOH.` - This statement is **incorrect** because `I⁻` is not related to `CH₃COOH`; it is the conjugate base of `HI`. - **Option 3:** `CH₃COOH is the conjugate acid of CH₃COOH.` - This statement is **incorrect** because `CH₃COOH` is not its own conjugate acid; `CH₃COOH₂⁺` is the conjugate acid. - **Option 4:** `CH₃COOH is the conjugate acid of CH₃COOH₂⁺.` - This statement is **incorrect** because `CH₃COOH₂⁺` is the conjugate acid of `CH₃COOH`, not the other way around. 4. **Conclusion:** - The incorrect statements are Options 2, 3, and 4. ### Final Answer: The incorrect statements are: - Option 2: `I⁻ is the conjugate base of CH₃COOH.` - Option 3: `CH₃COOH is the conjugate acid of CH₃COOH.` - Option 4: `CH₃COOH is the conjugate acid of CH₃COOH₂⁺.`
To solve the question regarding the equilibrium equation `CH₃COOH + HI ⇌ CH₃COOH₂⁺ + I⁻`, we need to analyze the statements provided and determine which ones are incorrect. ### Step-by-Step Solution: 1. **Identify the Acid and Base in the Reaction:** - In the reaction, `CH₃COOH` (acetic acid) donates a proton (H⁺) to form `CH₃COOH₂⁺` (the conjugate acid). - `HI` (hydroiodic acid) also donates a proton to form `I⁻` (iodide ion). ...
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