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Statement-1: I(2) +I to I(3) in abo...

Statement-1: `I_(2) +I to I_(3)` in above reaction `I_(2)` is Lewis base and
Statement-2: Electron pair acceptor is Lewis base.

A

Statement-1 is true , statement-2 is true and statement-2 is a correct explanation of statement-1.

B

Statement-1 is true statement-2 is true and statement-2 is not a correct explanation for statement-1.

C

Statement-1 is true statement -2 is false.

D

Statement-1 is false statement -2 is false.

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will break down each statement step by step. ### Step 1: Understanding the Reaction The reaction given is: \[ I_2 + I^- \rightarrow I_3^- \] Here, \( I_2 \) is iodine, and \( I^- \) is the iodide ion. ### Step 2: Identifying Lewis Bases and Acids - **Lewis Base**: A Lewis base is defined as an electron pair donor. - **Lewis Acid**: A Lewis acid is defined as an electron pair acceptor. ### Step 3: Analyzing Statement 1 **Statement 1**: "In the above reaction, \( I_2 \) is a Lewis base." - In the reaction, \( I^- \) (the iodide ion) donates an electron pair to \( I_2 \) to form \( I_3^- \). - Since \( I^- \) is donating the electron pair, it is the Lewis base in this reaction. - Therefore, \( I_2 \) is not acting as a Lewis base; instead, it is the species being accepted by the electron pair from \( I^- \). **Conclusion for Statement 1**: False. ### Step 4: Analyzing Statement 2 **Statement 2**: "Electron pair acceptor is a Lewis base." - This statement is incorrect because an electron pair acceptor is defined as a Lewis acid, not a Lewis base. - A Lewis base donates electron pairs, while a Lewis acid accepts them. **Conclusion for Statement 2**: False. ### Final Conclusion Both statements are false: - **Statement 1**: False (because \( I^- \) is the Lewis base). - **Statement 2**: False (because electron pair acceptor is a Lewis acid). ### Answer The correct option is that both statements are false. ---
To analyze the statements provided in the question, we will break down each statement step by step. ### Step 1: Understanding the Reaction The reaction given is: \[ I_2 + I^- \rightarrow I_3^- \] Here, \( I_2 \) is iodine, and \( I^- \) is the iodide ion. ### Step 2: Identifying Lewis Bases and Acids ...
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