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The conjugate base of [Al(H(2)O)(3) (OH)...

The conjugate base of `[Al(H_(2)O)_(3) (OH)_(3)` is 

A

`[A(H_(2)O)_(3)(OH)_(2)]^(+)`

B

`[Al(H_(2)O)_(3)(OH)_(2)O]`

C

`(Al(H_(2)O)_(3).(OH)_(3)]`

D

`[Al(H_(2)O)_(2)(OH)_(4)]^(-)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the conjugate base of the complex ion \([Al(H_2O)_3(OH)_3]\), we follow these steps: ### Step 1: Identify the Acid The given species \([Al(H_2O)_3(OH)_3]\) can act as an acid. In acid-base chemistry, an acid is a species that can donate a proton (H\(^+\)). ### Step 2: Determine the Loss of Proton When the acid \([Al(H_2O)_3(OH)_3]\) donates a proton, it will lose one of its hydrogen ions. This can occur from one of the hydroxide (OH\(^-\)) groups or from the water molecules (H\(_2\)O). ### Step 3: Write the Conjugate Base After losing a proton, the resulting species will be the conjugate base. The loss of one H\(^+\) ion from \([Al(H_2O)_3(OH)_3]\) leads to: \[ [Al(H_2O)_3(OH)_3] - H^+ \rightarrow [Al(H_2O)_3(OH)_2]^{-} \] ### Step 4: Finalize the Conjugate Base Thus, the conjugate base of \([Al(H_2O)_3(OH)_3]\) is: \[ [Al(H_2O)_3(OH)_2]^{-} \] ### Conclusion The conjugate base of \([Al(H_2O)_3(OH)_3]\) is \([Al(H_2O)_3(OH)_2]^{-}\).
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