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[NiCl(4)]^(2-) is paramagnetic while [Ni...

`[NiCl_(4)]^(2-)` is paramagnetic while `[Ni(CO)_(4)]` is diamagnetic though both are tetrahedral Why?

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In `[Nicl_(4)]^(2-)`, `Ni.is +2` oxidation state with the configuration `3d^(8) 4s^(@)`. Cr is weak ligand. It cannot pair up the electrons in 3d orbitals. Hence, it is paramagnetic. In `[Ni(CO)_(4)]` Ni is in zero oxidation state with the configuration `3d^(8) 4s^(2)` In the presence of CO ligand, the 4s electrons shift to 3d to pair up 3d electrons. Thus, there is no unpaired electron present. Hence, it is diamagnetic.
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