Home
Class 12
CHEMISTRY
The compound Co(en)(2)(NO(2))(2)Cl has b...

The compound `Co(en)_(2)(NO_(2))_(2)Cl` has been prepared in these isomeric forms `A,B` and `C`. A does not react with `AgNO_(3)` or (en) and is optically inactive, `B` reacts with `AgNO_(3)` but not with `(en)` and is optically inactive, `C` is optically active and reacts with both `AgNO_(3)` and (en). Identify each of these isomeric forms and draw their structures .

Promotional Banner

Similar Questions

Explore conceptually related problems

The compound [CrCl_(2)(NH_(3))_(2)(en)] can form .

The compound PtCI_(2) 2NH_(3) does not react with AgNO_(3) This compound can be represented as

Complex X of composition Cr(H_(2)O)_(6)Cl_(n) has a spin only mangnetic moment of 3.83 BM. It reacts with AgNO_(3) and shows geometrical isomerism. The IUPAC nomenclature of X is

CoSO_(4)Cl.5 NH_(3) exists in two isomeric forms 'A' and 'B'. Isomer 'A' reacts with AgNO_(3) to give white precipitate, but does not react with BaCl_(2) . Isomer 'B' gives white precipitate with BaCl_(2) but does not react with AgNO_(3) . Answer the following questions. (a) Identify 'A' and 'B' and write their structural formulae. (b) Name the type of isomerism involved. (c) Give the IUPAC name of 'A' and 'B'.

An optically active compound [A] C_(5)H_(13)N reacts with alkaline CHCl_(3) to give an optically active, compound [B]. [A] also reacts with nitrous acid to give an optically inactive alcohol [C] C_(5)H_(11)OH as the major product. What would be the structure of [A]?

Assertion: [CoCl_(3)(NH_(3))_(3)] does not give white precipitate with AgNO_(3) solution. Reason: [CoCl_(3)(NH_(3))_(3)] complex is optically inactive.

Which of the following halides react(s) with AgNO_(3)(aq) to give a precipitate that dissolves in Na_(2)S_(2)O_(3)(aq)

A Complex P of compositon Cr(H_2O)_(6)Br_(n) has a spin only magnetic moment of 3.83 BM . It reacts with AgNO_3 and shows geometrical isomerism. The IUPAC nomenclature of P is

Optically active isomer (A) of (C_(5)H_(9)Cl) on treatment with one mole of H_(2) gives an optically inactive compound (B) compound (A) will be :