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If the configuration of manganese is [Ar...

If the configuration of manganese is `[Ar]3d^(5),4s^(2)`, then maximum oxidation number of manganese will be

A

`+7`

B

`+6`

C

`+2`

D

`+4`

Text Solution

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The correct Answer is:
To determine the maximum oxidation number of manganese (Mn) with the electron configuration [Ar] 3d^5 4s^2, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Electron Configuration**: The electron configuration of manganese is given as [Ar] 3d^5 4s^2. This means manganese has 5 electrons in the 3d subshell and 2 electrons in the 4s subshell. 2. **Count the Total Valence Electrons**: To find the maximum oxidation state, we need to consider the total number of valence electrons that manganese can lose. The valence electrons are those in the outermost shell, which includes both the 4s and 3d electrons. - Total valence electrons = 5 (from 3d) + 2 (from 4s) = 7 electrons. 3. **Determine the Maximum Oxidation State**: The maximum oxidation state of an element corresponds to the total number of electrons that can be lost. For manganese, it can lose all 7 valence electrons. - Therefore, the maximum oxidation number = +7. 4. **Conclusion**: Based on the above calculations, the maximum oxidation number of manganese is +7. ### Final Answer: The maximum oxidation number of manganese (Mn) is +7. ---
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