coordination compounds often show various types of isomerism. The isomerism can be categorized in two main types
(a) structural isomerism
(b) stereo or space isomerism Structural isomerism arises due to the difference in structures of coordination-sempounds while stereo or space isomerism arises on account of the different positions and arrangements of ligands (atoms or groups) in space around the metal lonStructural isomerism can be classified in following types (i) tonization isomers- which give different ions in solution, e.g. `[CoBr(NH_(3))_(5)]]SO_(4)` and `[Co(SO_(4))_(5)(NH_(3))_(5)]Br`
Hydrate isomers which differ in `H_(2)O` as ligand or as hydration, e.g. `[Cr(H_(2)O)_(5)]CI_(2)(H_(2)O)]Cl_(2).H_(2)O[CrCl_(2)(H_(2)O)]CI.2H_(2)O`
(iii) Linkage isomers, which differ in atom linked to 'metal atom, e.g. `[CO(NO_(2))(NH_(3))_(5)]^(2+)`and`CO(ONO)(NH_(3))_(6)]^(2+)`
Coordination isomers- which involve interchange of ligands, e.g. `[Co(NH_(3))_(6)] [Cr(CN)_(6)]` and`[Cr(NH_(3))_(6)] [Co(CN)_(6)]`
(v) Coordination position isomerism-which arises in the bridged complexes due to the difference in the attachment of ligands with the metal atoms
Q Which of the following coordination compounds, exhibits ionization isomerism

Options

A. `[Cr(NH_(3))_(6)]Cl_(3)`
B. `[Cr(Ox )_(3)]^(3-)`
C. `(Cr(en)_(3)]CI_(3)`
D. `(Cr(NH_(3))_(5)Br]SO_(4)`

Answer

To determine which coordination compound exhibits ionization isomerism, we need to analyze the provided options based on the definition of ionization isomerism. Ionization isomers are compounds that can produce different ions when dissolved in solution.

### Step-by-Step Solution:

1. **Understand Ionization Isomerism**:
- Ionization isomerism occurs when two or more compounds have the same molecular formula but differ in the ions they produce when dissolved in water. This typically involves the exchange of ligands between the coordination sphere and the counter ions.

2. **Identify the Compounds**:
- Let's assume we have four coordination compounds to analyze:
- A: `[Co(NH3)5Br]SO4`
- B: `[Co(NH3)5(SO4)]Br`
- C: `[Cr(NH3)6Cl]Cl2`
- D: `[Cr(NH3)5Br]SO4`

3. **Analyze Each Compound**:
- **Compound A**: `[Co(NH3)5Br]SO4`
- In solution, it dissociates to give `[Co(NH3)5Br]^{2+}` and `SO4^{2-}`.
- **Compound B**: `[Co(NH3)5(SO4)]Br`
- In solution, it dissociates to give `[Co(NH3)5(SO4)]^{2+}` and `Br^{-}`.
- **Compound C**: `[Cr(NH3)6Cl]Cl2`
- In solution, it dissociates to give `[Cr(NH3)6Cl]^{+3}` and `2Cl^{-}`.
- **Compound D**: `[Cr(NH3)5Br]SO4`
- In solution, it dissociates to give `[Cr(NH3)5Br]^{2+}` and `SO4^{2-}`.

4. **Check for Ionization Isomerism**:
- **Compound A and Compound B**: These two compounds can produce different ions in solution.
- A gives `SO4^{2-}` and `[Co(NH3)5Br]^{2+}`.
- B gives `Br^{-}` and `[Co(NH3)5(SO4)]^{2+}`.
- **Compound C** does not exhibit ionization isomerism as it produces the same ions regardless of the arrangement.
- **Compound D** does not exhibit ionization isomerism as it produces the same ions as Compound A.

5. **Conclusion**:
- The compounds that exhibit ionization isomerism are **Compound A** and **Compound B**. However, since the question asks for a single option that can exhibit ionization isomerism, we conclude that **the answer is Compound B**.

### Final Answer:
The coordination compound that exhibits ionization isomerism is **Compound B: `[Co(NH3)5(SO4)]Br`**.