coordination compounds often show various types of isomerism. The isomerism can be categorized in two main types
(a) structural isomerism
(b) stereo or space isomerism Structural isomerism arises due to the difference in structures of coordination-sempounds while stereo or space isomerism arises on account of the different positions and arrangements of ligands (atoms or groups) in space around the metal lonStructural isomerism can be classified in following types (i) tonization isomers- which give different ions in solution, e.g. `[CoBr(NH_(3))_(5)]]SO_(4)` and `[Co(SO_(4))_(5)(NH_(3))_(5)]Br`
Hydrate isomers which differ in `H_(2)O` as ligand or as hydration, e.g. `[Cr(H_(2)O)_(5)]CI_(2)(H_(2)O)]Cl_(2).H_(2)O[CrCl_(2)(H_(2)O)]CI.2H_(2)O`
(iii) Linkage isomers, which differ in atom linked to 'metal atom, e.g. `[CO(NO_(2))(NH_(3))_(5)]^(2+)`and`CO(ONO)(NH_(3))_(6)]^(2+)`
Coordination isomers- which involve interchange of ligands, e.g. `[Co(NH_(3))_(6)] [Cr(CN)_(6)]` and`[Cr(NH_(3))_(6)] [Co(CN)_(6)]`
(v) Coordination position isomerism-which arises in the bridged complexes due to the difference in the attachment of ligands with the metal atoms
QThe total number of possible isomers for the complex compound `[Cu^(ll)(NH_(3))_(4)] [Pt^(ll)Cl_(4)`]are

Options

A. 3
B. 6
C. 4
D. 5

Answer

To determine the total number of possible isomers for the coordination compound \([Cu^{II}(NH_3)_4][Pt^{II}Cl_4]\), we will analyze the types of isomerism applicable to this compound, particularly focusing on coordination isomerism.

### Step-by-Step Solution:

1. **Identify the Coordination Complexes**:
The given compound consists of two coordination complexes: \([Cu^{II}(NH_3)_4]\) and \([Pt^{II}Cl_4]\).

2. **Determine the Ligands**:
- For the copper complex: The ligands are \(NH_3\) (ammonia).
- For the platinum complex: The ligands are \(Cl\) (chloride).

3. **Analyze Coordination Isomerism**:
Coordination isomerism occurs when the ligands in the complexes can be interchanged between the two metal centers.

4. **Count the Possible Isomers**:
- Start with the original configuration: \([Cu(NH_3)_4][Pt(Cl)_4]\).
- Interchange one \(NH_3\) with one \(Cl\):
- First isomer: \([Cu(NH_3)_3Cl][Pt(NH_3)(Cl)_3]\)
- Interchange two \(NH_3\) with two \(Cl\):
- Second isomer: \([Cu(NH_3)_2Cl_2][Pt(NH_3)_2Cl_2]\)
- Interchange three \(NH_3\) with three \(Cl\):
- Third isomer: \([Cu(NH_3)Cl_3][Pt(NH_3)_3]\)
- The final configuration remains as is: \([Cu(NH_3)_4][Pt(Cl)_4]\).

5. **List All Isomers**:
- Isomer 1: \([Cu(NH_3)_4][Pt(Cl)_4]\)
- Isomer 2: \([Cu(NH_3)_3Cl][Pt(NH_3)(Cl)_3]\)
- Isomer 3: \([Cu(NH_3)_2Cl_2][Pt(NH_3)_2Cl_2]\)
- Isomer 4: \([Cu(NH_3)Cl_3][Pt(NH_3)_3]\)

6. **Conclusion**:
After analyzing the possible configurations, we find that there are a total of **4 isomers** for the coordination compound \([Cu^{II}(NH_3)_4][Pt^{II}Cl_4]\).

### Final Answer:
The total number of possible isomers for the complex compound \([Cu^{II}(NH_3)_4][Pt^{II}Cl_4]\) is **4**.