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Na(2)CO(3) cannot be used in place of (N...

`Na_(2)CO_(3)` cannot be used in place of `(NH_(4))_(2)CO_(3)` for the precipitation of group V because

A

`Na^(+)` interferes in the detection of group V

B

concentration of `CO_(3)^(2-)` is very low

C

`Na^(+)` will react with acid radicals

D

`Mg_(2+)` will precipitate as `MgCO_(3)` il present in the mixture

Text Solution

Verified by Experts

`Na_(2)CO_(3)` is highly ionizable electrolyte which produces very high concentration of `CO_(3)^(2-)` ions. As a result ionic product of `MgCO_(3)` may increase its K, and it may get precipitated along with the radicals of group V.
Hence, (D) is the correct answer.
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