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Which is the correct order of K for Cus,...

Which is the correct order of K for Cus, ZnS and CdS?

A

CuS gt ZnS gt Cds

B

COS gt Cus gt ZnS

C

ZnS gt CDS gt Cus

D

ZnS gt Cus gt Cds

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order of the solubility product constant (K) for copper sulfide (CuS), zinc sulfide (ZnS), and cadmium sulfide (CdS), we can follow these steps: ### Step 1: Understand the Concept of Solubility Product Constant (K) The solubility product constant (K) is a measure of the solubility of a compound in water. It is defined as the product of the concentrations of the ions in a saturated solution of the compound, raised to the power of their coefficients in the balanced equation. ### Step 2: Write the Dissociation Reactions For each sulfide: - CuS(s) ⇌ Cu²⁺(aq) + S²⁻(aq) - ZnS(s) ⇌ Zn²⁺(aq) + S²⁻(aq) - CdS(s) ⇌ Cd²⁺(aq) + S²⁻(aq) ### Step 3: Identify the Cations and Anions In all three compounds, the anion (S²⁻) is the same. The cations differ: - Cu²⁺ for CuS - Zn²⁺ for ZnS - Cd²⁺ for CdS ### Step 4: Analyze the Polarizability and Ionic Character The polarizability of cations affects the covalent character of the sulfides: - Cu²⁺ has the highest polarizing power, making CuS more covalent. - Cd²⁺ has moderate polarizing power, making CdS less covalent than CuS but more than ZnS. - Zn²⁺ has the lowest polarizing power, making ZnS the most ionic. ### Step 5: Determine the Relationship Between Covalent Character and K More covalent character in a compound typically results in lower solubility, hence a lower K value. Conversely, more ionic character results in higher solubility and a higher K value. ### Step 6: Establish the Order of K Based on the analysis: - CuS (most covalent, lowest K) - CdS (moderate covalent character, intermediate K) - ZnS (most ionic, highest K) Thus, the order of K for the compounds is: **K(CuS) < K(CdS) < K(ZnS)** ### Final Answer The correct order of K for CuS, ZnS, and CdS is: **K(CuS) < K(CdS) < K(ZnS)**
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