What is the product obtained when MnSO4, in solution is boiled with sodium bismuthate and concentrated `HNO_3`?

Options

A. `MnO_2`
B. `HMnO_4`
C. `Mn_3O_4`
D. `PbMnO_4`

Answer

To determine the product obtained when manganese sulfate (MnSO4) is boiled with sodium bismuthate (NaBiO3) and concentrated nitric acid (HNO3), we can follow these steps:

### Step 1: Identify Reactants
The reactants in this reaction are:
- Manganese sulfate (MnSO4)
- Sodium bismuthate (NaBiO3)
- Concentrated nitric acid (HNO3)

### Step 2: Understand the Reaction Type
This reaction is a redox reaction. In redox reactions, oxidation and reduction occur simultaneously. Here, manganese is oxidized, and bismuth is reduced.

### Step 3: Write the Reaction
When MnSO4 is boiled with NaBiO3 and concentrated HNO3, the following products are formed:
- Bismuth nitrate (Bi(NO3)3)
- Sodium sulfate (Na2SO4)
- Sodium nitrate (NaNO3)
- Manganese(VII) oxide (HMnO4)
- Water (H2O)

### Step 4: Balance the Reaction
To balance the reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced equation can be represented as follows:

\[ 2 \text{MnSO}_4 + 5 \text{NaBiO}_3 + 16 \text{HNO}_3 \rightarrow 2 \text{HMnO}_4 + 5 \text{Bi(NO}_3)_3 + 5 \text{Na}_2\text{SO}_4 + 7 \text{H}_2\text{O} \]

### Step 5: Identify the Main Product
From the balanced equation, we can see that the main product of interest is:
- Manganese(VII) oxide (HMnO4)

### Conclusion
The product obtained when MnSO4 is boiled with sodium bismuthate and concentrated HNO3 is **HMnO4**.