Home
Class 12
CHEMISTRY
A scarlet compound (A) is treated with c...

A scarlet compound (A) is treated with conc. `HNO_3` to give a chocolate brown precipitate (B) and a colourless solution of C, On adding Kl to this solution, a yellow ppt. (D) is obtained. The precipitate (B) on warming with conc. `HNO_3` in the presence of `Mn(NO_(3))_2` prdouces a pink coloured solution due to the formation of (E). What is (E)?

A

`PbMnO_4`

B

`PbI_2`

C

`MnO_2`

D

`HMnO_4`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

A scalet compound A is treated with concenbtrated HNO_(3) to gave a chocolate brown precipitate B. The precipitate is filtered and the filtrate is neurralised with NaOH Addition of KI to the resulting solution gives a yellow precipitate C the brown precipitate B on warming with concentrated HNO_(3) in the presence of Mn(NO_(3))_(2) produces a pink coloured solution due to the formation of D identify A, B,C, and D write the reaction sequence.

Brown ppt ,of Mn(OH)_2 on boiling with PbO_(2) and cone HNO_(3) yields a pink colouration on dilution due to the formation of

A precipitate of ……would be obtained on adding HCI to a solution of As_(2)S_(3) in yellow ammonium salphide

On adding KI to a metal salt solution, no precipitate was observed but the salt solution gives yellow precipitate with K_(2)CrO_(4) in the presence of CH_(3)COOH . Then the salt is:

Assertion: A solution of AgCl in NH_(4)OH gives a white precipitate when acidified with HNO_(3) . Reason: [Ag(NH_(3))_(2)]^(+) decomposes in the presence of HNO_(3) .

When compound (A) is treated with conc. H_(2)SO_(4) , a reddish brown colour gas (B) is evolved. To this solution, a solution of (C ) is added slowly from the side of the test tube, a blue ring is obtained at the junction of two layers due to formation of (D). Compound (D) has formula :

A black coloured compound (A) on reaction with dilute H_(2)SO_(4) gives a gas (B) which on passing in a solution of an acid ( C) gives a white turbidity (D) .Gas (B) when passed in an acidified solution of a compound (E) gives a precipitate (F) soluble in dilute HNO_(3) .After boiling this solution when an excess of NH_(4)OH is added a intense blue coloured compound (G) is formed. To this solution on addition of acetic acid and aqueous K_(4)[Fe(CN)_(6)] a chocolate brown precipitate (H) is obtained.On addition of an aqueous solution of BaCl_(2) to an aqueous solution of (E) a white precipitate insoluble in dilute HCl is obtained. Identify the compounds from (A) to (H) .

A white crystalline substance dissolves in hot water. On passing H_(2)S in this solution, black precipitate is obtained. The black precipitate dissolves completely in hot HNO_(3) . On adding a few drops of conc. H_(2)SO_(4) , a white precipitate is obtained. this substance is :

Colourless salt (A) decolourise I_(2) solution and gives white precipitate (change to black) with AgNO_(3) solution. (A) also produces pink colour with FeCl_(3) solution. Identify (A) and explain reactions.

A white sodium salt dissolves in water to give a solution which is neutral to litmus.When silver nitrate solution is added to the solution, a white precipitate is obtained which does not dissolve in dilute HNO_(3) .The anion is