If sucrose is treated with conc. `H_(2)SO_(4)`, the product formed is

Options

A. `CO_(2)`
B. `C`
C. `CO`
D. `H_(2)O`

Answer

To solve the question regarding the reaction of sucrose with concentrated sulfuric acid (H₂SO₄), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Chemical Structure of Sucrose**:
- Sucrose is a disaccharide composed of glucose and fructose. Its chemical formula is C₁₂H₂₂O₁₁.

2. **Understanding the Reaction with Concentrated H₂SO₄**:
- Concentrated sulfuric acid is a strong dehydrating agent. When sucrose is treated with concentrated H₂SO₄, it removes water (H₂O) from the sucrose molecule.

3. **Dehydration Process**:
- The dehydration of sucrose leads to the breakdown of its molecular structure. The sulfuric acid removes water molecules, resulting in the formation of carbon (C) and water (H₂O).

4. **Balanced Reaction**:
- The reaction can be summarized as:
\[ C_{12}H_{22}O_{11} \xrightarrow{H_2SO_4} 12C + 11H_2O \]
- Here, 12 moles of carbon and 11 moles of water are produced.

5. **Observation of the Reaction**:
- The heat generated during the reaction causes the water to vaporize, leading to the formation of a black column of carbon.

6. **Conclusion**:
- The products of the reaction between sucrose and concentrated sulfuric acid are carbon and water.

### Final Answer:
The product formed when sucrose is treated with concentrated H₂SO₄ is **carbon (C) and water (H₂O)**.

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