Home
Class 12
CHEMISTRY
"Glucose"+HNO(3) to "Product(P)" Find ...

`"Glucose"+HNO_(3) to "Product(P)"`
Find ratio of `(" no. of -COOH group in P")/("no. of -OH group in P")?`

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the reaction of glucose with nitric acid (HNO3) and determine the number of carboxylic acid groups (-COOH) and hydroxyl groups (-OH) in the product formed. ### Step-by-Step Solution: 1. **Identify the Structure of Glucose**: - Glucose is a six-carbon aldose sugar with the molecular formula C6H12O6. It contains one aldehyde group (-CHO) and five hydroxyl groups (-OH). 2. **Understand the Role of HNO3**: ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Glucose reacts with HNO_(3) to form

P ( major product ), P is

Product P & Q may be grouped as

-OCH_(3) group is weaker +R group than -OH

How do yout explain the presence of five -OH groups in glucose molecule?

alpha- and beta- Glucose differ in the orientation of the (-OH) group around:

Conc HNO_(3) is added before proceeding to test for group III. This is to

Few drop of HNO_(3) are added to II group if before preceeding to group III in order to :