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Treatment of (CH(3))(3)C CH(OH)CH(3) wit...

Treatment of `(CH_(3))_(3)C CH(OH)CH_(3)` with conc, hydrochloric acid gives two isomeric alkyl chorides. What are there two products?

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To solve the problem of identifying the two isomeric alkyl chlorides formed from the treatment of `(CH₃)₃C CH(OH)CH₃` with concentrated hydrochloric acid, we can follow these steps: ### Step 1: Identify the Structure of the Alcohol The given compound is `(CH₃)₃C CH(OH)CH₃`. This can be represented as: - A tert-butyl group `(CH₃)₃C-` - A secondary alcohol `-CH(OH)CH₃` ### Step 2: Protonation of the Alcohol ...
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