Which of the following will give yellow precipitate with `l_(2)//NaOH`?

Options

A. `CH_(3)-CO-O-CO-CH_(3)`
B. `I-CH_(2)-overset(O)overset(||)C-CH_(2)-CH_(3)`
C. `CH_(3)-CO-NH_(2)`
D. `CH_(3)-overset(OH)overset(|)CH-CH_(2)-CH_(3)`

Explanation

To determine which compound will give a yellow precipitate with iodine (I2) in the presence of sodium hydroxide (NaOH), we need to understand the reaction involved. The yellow precipitate is typically associated with the formation of iodoform (CHI3), which occurs when a compound contains either a methyl ketone (RCOCH3) or an alcohol that can be oxidized to a methyl ketone.

### Step-by-Step Solution:

1. **Identify the Functional Groups**:
We need to examine each of the given options to identify if they contain the necessary functional groups that can react with I2 and NaOH to produce a yellow precipitate.

2. **Analyze Each Option**:
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