Compare the following displacement reactions and account for any difference
(a) `ROH+NaBrto`
(b) `ROH+HBrto`

Explanation

To compare the displacement reactions of alcohol with sodium bromide (NaBr) and hydrogen bromide (HBr), we will analyze each reaction step by step.

### Step 1: Analyze the first reaction `ROH + NaBr`
In this reaction, we have an alcohol (ROH) reacting with sodium bromide (NaBr). The expected reaction would be:

\[ \text{ROH} + \text{NaBr} \rightarrow \text{RBr} + \text{NaOH} \]

Here, we would expect the bromide ion (Br⁻) to replace the hydroxyl group (OH⁻) in the alcohol. However, this reaction does not occur.
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