Iodoform gives precipitate with `AgNO_(3)` on heating while `CHCl_(3)` does not, why?

[Co(NH_3)_5SO_4] Br gives yellow precipitate with AgNO_3 solution while [Co(NH_3)_5Br]SO_4 does not why ?

NaCl_((aq)) gives a white precipitate with AgNO_(3) solution but C Cl_(4) or CHCl_(3) does not , because

NaBr gives pale yellow precipitate with AgNO_(3) solution but CBr_(4) does not. Why ?

AgNO_(3) gives red precipitate with

A compound with the empirical formula Co(NH_(3))_(5)SO_(4) Br exists in two forms viz red and violet forms Solution of red form gives a precipitate of AgBr with AgNO_(3) solution The violet form gives no precipitate with AgNO_(3) but gives white precipitate with the aquous solution of BaCI_(2) From the these observations give the structure of each form .

Br_(2)+NaOH overset(R.T.) to Y+Z If Y gives precipitate with AgNO_(3) , then Z does not undergo reaction with:

Br_(2)+NaOH overset(R.T.) to Y+Z If Y gives precipitate with AgNO_(3) , then Z does not undergo reaction with:

"CCl"_(4) does not give a precipitate with "AgNO"_(3) . The reason is :

An aqueous solution of salt gives salt precipitate with AgNO_(3) solution as well as with dilute H_(2)SO_(4) . It may be

A complex compound which is formed by ligands nitrate and chloride. It gives two moles of AgCl precipitate with AgNO_(3) . What will be its formulae :