In `CH_(3)-CH_(2)-CH_(2)-Br,C-Br` bond is formed by the overlapping of

Options

A. `2sp^(3)-2p_(z)`
B. `2sp^(3)-3p_(z)`
C. `2sp^(3)-3p_(z)`
D. `2sp^(3)-4p_(z)`

Answer

To determine how the C-Br bond is formed in the compound CH₃-CH₂-CH₂-Br, we need to analyze the types of orbitals involved in the bond formation between carbon and bromine.

### Step-by-Step Solution:

1. **Identify the Structure**: The compound CH₃-CH₂-CH₂-Br consists of a straight-chain alkane with a bromine atom attached to the terminal carbon. The carbon atoms are sp³ hybridized due to their tetrahedral geometry.

2. **Determine the Hybridization of Carbon**: In this molecule, each of the three carbon atoms (the terminal and the two in the chain) is sp³ hybridized. This means that each carbon atom has four sp³ hybrid orbitals.

3. **Identify the Bromine Atom**: Bromine (Br) is in group 17 of the periodic table and has an electronic configuration of [Ar] 4s² 4p⁵. In the context of bond formation, we focus on the p orbitals, specifically the 4p orbitals.

4. **Determine the Orbital Overlap**: The bond between carbon and bromine (C-Br) is formed by the overlap of one of the sp³ hybrid orbitals from carbon with one of the p orbitals from bromine. Since bromine has five electrons in the 4p subshell, one of these p orbitals (specifically 4p) will be involved in the bond formation.

5. **Specify the Orbital Types**: The specific orbitals involved in the bond formation are:
- The sp³ orbital from carbon (C)
- The 4p orbital from bromine (Br)

6. **Final Conclusion**: Therefore, the C-Br bond is formed by the overlapping of an sp³ orbital from carbon and a 4p orbital from bromine.

### Final Answer:
The C-Br bond in CH₃-CH₂-CH₂-Br is formed by the overlapping of an sp³ orbital from carbon and a 4p orbital from bromine.

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