`H_(2)C=CH-Cloverset(HCl)toA`. A is

Options

A.
B.
C.
D.

Answer

To solve the question, we need to determine the product A when vinyl chloride (H₂C=CH-Cl) reacts with HCl.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactant is vinyl chloride, which has the structure H₂C=CH-Cl. This compound features a double bond between two carbon atoms, with one of the carbons bonded to a chlorine atom.

2. **Understand the Reaction**:
The reaction involves the addition of HCl to the alkene (vinyl chloride). In such reactions, we typically follow Markovnikov's rule, which states that when HX (where X is a halogen) is added to an alkene, the hydrogen atom (H) will attach to the carbon with the greater number of hydrogen atoms, while the halogen (Cl) will attach to the carbon with fewer hydrogen atoms.

3. **Apply Markovnikov's Rule**:
In vinyl chloride (H₂C=CH-Cl):
- The first carbon (C1) has 2 hydrogen atoms (H₂C).
- The second carbon (C2) has 1 hydrogen atom (CH).
According to Markovnikov's rule, the Cl (the negative part of HCl) will attach to the carbon with fewer hydrogen atoms (C2), and H (the positive part of HCl) will attach to the carbon with more hydrogen atoms (C1).

4. **Draw the Product**:
After the addition of HCl:
- C1 will gain an H atom, becoming CH₃ (methyl group).
- C2 will gain a Cl atom, becoming CHCl (with one hydrogen atom remaining).
Therefore, the product A will be CH₃-CHCl-CH₃, which can also be represented as 1-chloro-2-propene.

5. **Final Structure of Product A**:
The final structure of product A is CH₃-CHCl-CH₃ (1-chloro-2-propene).

### Summary of the Product:
The product A formed from the reaction of vinyl chloride with HCl is 1-chloro-2-propene (CH₃-CHCl-CH₃).