The products formed when bromocyclohexane and sodium propynide are heated together are

Options

A. 1-cyclohexylpropyne
B. cyclohexene
C. propyne
D. 2-cyclohexylpropyne

Answer

To determine the products formed when bromocyclohexane and sodium propynide are heated together, we can follow these steps:

### Step 1: Identify the Reactants
- **Bromocyclohexane**: This is a cyclohexane ring with a bromine atom attached. The structure can be represented as C6H11Br.
- **Sodium Propynide**: This is the sodium salt of propyn-1-yne, represented as CH3C≡C⁻Na⁺. It contains a triple bond between two carbon atoms.

### Step 2: Understand the Mechanism
- The reaction involves a nucleophilic substitution where the nucleophile (the carbon in sodium propynide) attacks the electrophilic carbon in bromocyclohexane. The bromine atom is a good leaving group due to its electronegativity.

### Step 3: Nucleophilic Attack
- The negatively charged carbon (C⁻) from sodium propynide will attack the carbon atom in bromocyclohexane that is bonded to the bromine atom. This will lead to the displacement of the bromine atom.

### Step 4: Formation of Products
- When the nucleophilic attack occurs, the bromine atom leaves as bromide ion (Br⁻), and a new bond is formed between the carbon of the sodium propynide and the carbon of the bromocyclohexane.
- The sodium ion (Na⁺) will combine with the bromide ion (Br⁻) to form sodium bromide (NaBr).

### Step 5: Structure of the Product
- The resulting compound will be a substituted cyclohexane with a propynyl group attached. The structure can be represented as:
- 1-Propynylcyclohexane (where the propynyl group is attached to the cyclohexane ring).

### Conclusion
- The final products of the reaction between bromocyclohexane and sodium propynide upon heating are:
- **1-Propynylcyclohexane**
- **Sodium bromide (NaBr)**

### Final Answer
The products formed when bromocyclohexane and sodium propynide are heated together are 1-Propynylcyclohexane and sodium bromide (NaBr).

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