STATEMENT-1: 2-Methyl-2-butene is the acid catalysed dehydration product of neopentyl alcohol.
and
STATEMENT-2: Neopentyl carbocation is the intermediate of the product

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for statement-2
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-2
C. Statement-1 is True, Statement-2 is False
D. Statement-1 is False, Statement-2 is True

Answer

To solve the question, we need to analyze both statements regarding neopentyl alcohol and its dehydration product.

### Step-by-Step Solution:

1. **Identify Neopentyl Alcohol Structure**:
Neopentyl alcohol (2-methyl-2-butanol) has the structure:
\[ \text{(CH}_3\text{)}_4\text{C(OH)} \]
This structure indicates that the hydroxyl (-OH) group is attached to a carbon that is connected to four other carbons.

2. **Acid-Catalyzed Dehydration**:
When neopentyl alcohol undergoes acid-catalyzed dehydration, concentrated sulfuric acid (H₂SO₄) is used. The -OH group will protonate, making it a better leaving group (water).

3. **Formation of Neopentyl Carbocation**:
Upon dehydration, the -OH group leaves, forming a neopentyl carbocation, which is a primary carbocation:
\[ \text{(CH}_3\text{)}_4\text{C}^+ \]
However, primary carbocations are less stable and typically undergo rearrangement.

4. **Rearrangement to More Stable Carbocation**:
The neopentyl carbocation can rearrange through a methyl shift to form a more stable tertiary carbocation (2-methyl-2-butyl carbocation):
\[ \text{(CH}_3\text{)}_2\text{C}^+\text{(CH}_2\text{)}_2\text{C}^+ \]

5. **Formation of the Alkene**:
The tertiary carbocation can lose a proton (H⁺) to form 2-methyl-2-butene:
\[ \text{(CH}_3\text{)}_2\text{C}=\text{C(CH}_3\text{)}_2 \]

6. **Evaluate Statements**:
- **Statement 1**: "2-Methyl-2-butene is the acid-catalyzed dehydration product of neopentyl alcohol." This is **true**.
- **Statement 2**: "Neopentyl carbocation is the intermediate of the product." This is **false** because the intermediate is actually the more stable tertiary carbocation formed after rearrangement.

### Conclusion:
- **Statement 1** is true.
- **Statement 2** is false.

Thus, the answer is that Statement 1 is true and Statement 2 is false.