The reaction `C_(6)H_(5)CH=CHCHO` with `NaBH_(4)` yields

Options

A. `C_(6)H_(5)CH_(2)CH_(2)OH`
B. `C_(6)H_(5)CH=CHCH_(2)OH`
C. `C_(6)H_(5)CH_(2)CH_(2)CHO`
D. `C_(6)H_(5)CHOHCH_(3)`

Answer

To solve the question regarding the reaction of C₆H₅CH=CHCHO with NaBH₄, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The compound given is C₆H₅CH=CHCHO, which is an allylic aldehyde. It contains a phenyl group (C₆H₅), a double bond (C=CH), and an aldehyde functional group (CHO).

2. **Understand the Role of NaBH₄**:
Sodium borohydride (NaBH₄) is a well-known reducing agent. It is capable of reducing aldehydes to primary alcohols but does not reduce alkenes (double bonds).

3. **Identify Functional Groups**:
In the structure C₆H₅CH=CHCHO, the aldehyde group (CHO) is the functional group that will be reduced. The double bond (C=CH) will remain unchanged.

4. **Reduction of the Aldehyde**:
When NaBH₄ reacts with the aldehyde group, it will convert the aldehyde (CHO) into a primary alcohol (CH₂OH). The double bond (C=CH) will not be affected by the reaction.

5. **Write the Product**:
After the reduction, the structure will be:
- The phenyl group (C₆H₅) remains.
- The double bond (C=CH) remains unchanged.
- The aldehyde (CHO) is converted to an alcohol (CH₂OH).

Therefore, the final product will be:
\[ C₆H₅CH=CHCH₂OH \]

### Final Answer:
The product of the reaction of C₆H₅CH=CHCHO with NaBH₄ is C₆H₅CH=CHCH₂OH.