`CH-=CHoverset(NH_4Cl)underset(Cu_2Cl_2)rarr` product
product is:

Options

A. `Cu-C-=C-Cu`
B. `CH_2=CH-C-=CH`
C. `Ch-=C-Cu`
D. `Cu-C-=C-NH_4`

Answer

To solve the question regarding the reaction of acetylene (CH≡CH) with ammonium chloride (NH4Cl) in the presence of cuprous chloride (Cu2Cl2), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The reactant is acetylene, which is represented as CH≡CH. This compound is an alkyne with a carbon-carbon triple bond.

2. **Understand the Reaction Conditions:**
- The reaction occurs in the presence of NH4Cl and Cu2Cl2. Here, NH4Cl acts as a source of ammonium ions, while Cu2Cl2 provides cuprous ions (Cu+).

3. **Reaction Mechanism:**
- When acetylene (CH≡CH) reacts with cuprous chloride (CuCl) in the presence of ammonium chloride, it forms a complex known as copper(I) acetylide.
- The reaction can be summarized as follows:
\[ CH≡CH + NH4Cl + Cu2Cl2 \rightarrow CuC≡C Cu \]
- In this reaction, each carbon atom of the triple bond in acetylene forms a bond with a copper atom, resulting in the product CuC≡C Cu.

4. **Identify the Product:**
- The product formed from this reaction is copper(I) acetylide, represented as CuC≡C Cu. This indicates that both carbon atoms in the triple bond are bonded to copper atoms.

5. **Final Answer:**
- Therefore, the product of the reaction is CuC≡C Cu.