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Adolf von Baeyer suggested that, since c...

Adolf von Baeyer suggested that, since carbon prefers to have tetrahedral geometry with bond angles of approximately `109^@`, ring sizes other than five and six may be too strained to exist. Baeyer based his hypothesis on the simple geometrical notion that a three-membered ring (cyclopropane) should be an equilateral triangle with bond angles to `60^@`, a four membered ring (cyclobutane) should be a square with bond angles of `90^@` and so on. According to Baeyer's analysis, cyclopropane, with a bond angle compression of `109^@ - 60^@ = 49^@`, should have a large amount of angle strain and must therefore be highly reactive. Cyclohexane becomes puckered to releave its strain. The angular derivation of cycloalkane is` (-11^@)`. Greater is the angular deviation more is the torsional strain.
Which among the following is most strained cycloalkane?

A

Cyclopropane

B

Cyclobutane

C

Cyclopentene

D

Cyclohexane

Text Solution

AI Generated Solution

The correct Answer is:
To determine which cycloalkane is the most strained, we will analyze the bond angles and the resulting strain for each of the given cycloalkanes: cyclopropane, cyclobutane, cyclopentane, and cyclohexane. ### Step-by-Step Solution: 1. **Understanding the Geometry of Carbon:** - Carbon prefers a tetrahedral geometry with bond angles of approximately 109.5° due to its sp³ hybridization. 2. **Analyzing Cyclopropane:** - Cyclopropane has a three-membered ring structure. - The bond angles in cyclopropane are approximately 60°. - The angle strain can be calculated as: \[ \text{Angle Strain} = 109.5° - 60° = 49.5° \] - Cyclopropane is expected to have a large amount of angle strain due to this significant deviation from the ideal tetrahedral angle. 3. **Analyzing Cyclobutane:** - Cyclobutane has a four-membered ring structure. - The bond angles in cyclobutane are approximately 90°. - The angle strain can be calculated as: \[ \text{Angle Strain} = 109.5° - 90° = 19.5° \] - Cyclobutane also experiences angle strain, but it is less than that of cyclopropane. 4. **Analyzing Cyclopentane:** - Cyclopentane has a five-membered ring structure. - The bond angles in cyclopentane are approximately 108°. - The angle strain can be calculated as: \[ \text{Angle Strain} = 109.5° - 108° = 1.5° \] - Cyclopentane has minimal angle strain and is relatively stable. 5. **Analyzing Cyclohexane:** - Cyclohexane has a six-membered ring structure. - The bond angles in cyclohexane are approximately 120° in its chair conformation. - The angle strain can be calculated as: \[ \text{Angle Strain} = 109.5° - 120° = -10.5° \] - Cyclohexane is stable and has no significant angle strain. 6. **Conclusion:** - Comparing the angle strains: - Cyclopropane: 49.5° strain - Cyclobutane: 19.5° strain - Cyclopentane: 1.5° strain - Cyclohexane: -10.5° strain - The cycloalkane with the greatest angle strain is cyclopropane. ### Final Answer: **Cyclopropane is the most strained cycloalkane.**
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