If `a,b,c` are in HP,b,c,d are in GP and `c,d,e` are in AP, than show that `e=(ab^(2))/(2a-b)^(2)`.

If a,b,c are in H.P , b,c,d are in G.P and c,d,e are in A.P. , then the value of e is (a) (ab^(2))/((2a-b)^(2)) (b) (a^(2)b)/((2a-b)^(2)) (c) (a^(2)b^(2))/((2a-b)^(2)) (d) None of these

If a,b,c, are in A.P., b,c,d are in G.P. and c,d,e, are in H.P., then a,c,e are in

If a,b,c are in AP and b,c,d be in HP, then

If a,b,c,d,e be 5 numbers such that a,b,c are in A.P; b,c,d are in GP & c,d,e are in HP then prove that a,c,e are in GP

if a, b, c are in A.P., b, c, d are in G.P. and (1)/(c),(1)/(d),(1)/(e) are in A.P., then prove that a, c, e are in G.P.

If a,b,c,d,e are five numbers such that a,b,c are in A.P., b,c,d are in G.P. and c,d, e ar in H.P. prove that a,c,e are in G.P.

If a, b, c are in A.P., b, c, d are in G.P. and 1/c ,1/d ,1/e are in A.P. prove that a, c, e are in G.P.

If a, b, c are in A.P., b, c, d are in G.P. and 1/c ,1/d ,1/e are in A.P. prove that a, c, e are in G.P.

If a,b,c are in A.P., b,c,d are in G.P. and (1)/(c ),(1)/(d),(1)/(e ) are in A.P, prove that a,c,e are in G.P.

If a,b,c are in AP and a^(2),b^(2),c^(2) are in HP, then