If sum(r=1)^n tr=n/8(n+1)(n+2)(n+3), the...

If `sum_(r=1)^n t_r=n/8(n+1)(n+2)(n+3),` then find `sum_(r=1)^n1/(t_r)dot`

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The correct Answer is:

`(n^(2)+3n)/(2(n+1)(n+2))`

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