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A force F of constant magnitude acts on ...

A force F of constant magnitude acts on a block of mass 'm' and t=0,initially along positive x-direction. The direction of force F starts rotating with a constant angular velocity `omega` in anticlockwise sense. Then the magnitude of velocity of the block as a function of time 't' is ( initial block was at rest )

A

`(F)/( m omega ) sin ((omegat)/( 2))`

B

`(2F)/( m omega ) sin ((omegat)/( 2))`

C

`(F)/( 2 m omega) sin ((omegat)/( 2))`

D

`(2F)/( 3 m omega) sin ((omegat)/( 2))`

Text Solution

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The correct Answer is:
B
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