Home
Class 12
PHYSICS
The adjacent figure shows a non-uniform ...

The adjacent figure shows a non-uniform metre stick AB having the linear mass density variation `lambda = lambda_(0) x` , where `lambda_(0)` is a constant and x is the distance from end A, placed on a smooth horizontal surface. In the first experiment, the rod is pivoted at A and force F is applied perpendicular to the rod at the other end B and in the second experiment, the rod is pivoted at B and the force is applied perpendicular to the rod at the end A. If in the first case angular acceleration is `alpha_(A)` and in the second case it is `alpha_(B)` then

A

`alpha_(A) = alpha_(B)`

B

`alpha_(A) gt alpha_(B)`

C

`alpha_(A) lt alpha_(B)`

D

data insufficient to determine

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

Figure shows a rope of variable mass whose linear mass density is given by , lambda = Ax , where A is + ve constant and x is distance from left end . It bis placed on a smooth horizontal surface . A force F is acting on it as shown . (i) Find total mass of the rope . (ii) Find tension at point P.

Find coordinates of mass center of a non-uniform rod of length L whose linear mass density lambda varies as lambda=a+bx, where x is the distance from the lighter end.

A uniform rod of mass m , length l rests on a smooth horizontal surface. Rod is given a sharp horizontal impulse p perpendicular to the rod at a distance l//4 from the centre. The angular velocity of the rod will be

A rod hanging from ceiling has linear density given as lambda=m_0(1+x) kg/m, where m_0 is constant and x is distance of a point from free end . if the length of the rod is 4m then velocity of wave at x=1m is

A slender rod of mass M and length L rests on a horizontal frictionless surface. The rod is pivoted about one of ends. The impulse of the force exerted on the rod by the pivot when the rod is struck by a blow of impulse J perpendicular to the rod at other end is

A uniform rod of mass m and length l rests on a smooth horizontal surface. One of the ends of the rod is struck in a horizontal direction at right angles to the rod. As a result the rod obtains velocity v_(0) . Find the force with which one-half of the rod will act ont he other in the process of motion.

You are given a rod of length L. The linear mass density is lambda such that lambda=a+bx . Here a and b are constants and the mass of the rod increases as x decreases. Find the mass of the rod

A uniform rod AB of mass m and length l at rest on a smooth horizontal surface . An impulse P is applied to the end B . The time taken by the rod to turn through a right angle is :

A uniform rod AB of mass m and length l at rest on a smooth horizontal surface . An impulse P is applied to the end B . The time taken by the rod to turn through a right angle is :

A uniform straight rod is placed in vertical position on a smooth horizontal surface and released. As the rod is in motion, the centre of mass moves