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A part of a circuit in steady state alon...

A part of a circuit in steady state along with the currents flowing in the branches,the values of resistances,etc, is shown in figure.Calculate the energy stored in the capacitor.

Text Solution

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Your objective is to find out potential difference across the capacitor first. Applying Kirchoff.s junction law at A and B
`At A: 2 + 1 - I_(1)= 0, I_(1)= 3A`
`At B: I_(2) + 1 - 2 = 0, I_(2) =1 A`
Now, applying KVL in the mesh ADCBA (mesh means smallest loop or closed path)`V_(AB) = 20 V`
So, energy stored in the capacitor
`U=(1)/(2)CV^(2)=(1)/(2)xx(4xx10^(-6))xx(20)^(2)=8xx10^(-4)J`
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