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When a galvanometer is shunted with a 4O...

When a galvanometer is shunted with a `4Omega` resistance, the deflection is reduced to `1//5`. If the galvanometer is further shounted with a `2Omega` wire, the new deflection will be (assuming the main current remains the same)

A

`5//13` of the deflection when shunted with `4 Omega` only

B

`8//13` of the deflection when shunted with `4 Omega` only

C

`3//4` of the deflection when shunted with `4Omega` only

D

`3//13` of the deflection when shunted with `4Omega` only

Text Solution

Verified by Experts

The correct Answer is:
A
When only `4 Omega` resistance is
shunted, `(i_(g))_(1) = i//5`
`Gxxi//5 = 4 xx (4//5) implies G = 16Omega`
`(4//3)/(16+(4//3))i=(1)/(13)`itherefore Hence, (A) is correct
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