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In the given circuit, R(1) = 10Omega R(2...

 In the given circuit, `R_(1)` = `10Omega` `R_(2) = 6Omega` and E = 10V, then correct statement is

A

Effective resistance of the circuit is `20Omega`

B

Reading of A, is 1//2 amp

C

Reading of `A_(2)`` is 1//4 amp.

D

Reading of `A_(3)` is 1//8 amp

Text Solution

Verified by Experts

Potential difference across`R_(2)` is zero, therefore current Ay 100 100 100 100 in three branches is zero. Therefore, current in two roww w wwww branch containing `R_(1)` will be same and the circuit will 100 100 100 100 be simplified as shown
Effective resistance of the circuit`R_(eff)=(40xx40)/(40+40)=20Omega`
Current through the circuit `1=(10)/(20)=(1//2)` amp and reading of `A_(1)=(1)/(2)`amp and reading of
`A_(2)=(1)/(2)` amp
Hence, (A) (B).& (C) are correct
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