A galvanometer having 50 divisions provided with a variable shunt S is used to measure the current when connected in series with a resistance of `90 Omega` and a battery of internal resistance `10 Omega`. It is observed that when the shunt resistances are `10 Oemga` and `50 Omega`, the deflections are, respectively, 9 and 30 divisions. What is the resistance of the galvanometer

Explanation

To solve the problem, we need to determine the resistance of the galvanometer (G) using the information provided about the shunt resistances and the corresponding deflections.

### Step-by-Step Solution:

1. **Understanding the Circuit**:
- We have a galvanometer (G) with a variable shunt resistance (S) connected in parallel.
- The total resistance in series with the galvanometer is \( R = 90 \, \Omega + 10 \, \Omega = 100 \, \Omega \).

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