Home
Class 12
PHYSICS
Find the emf (V) and internal resistance...

Find the emf (`V`) and internal resistance `(R)` of a single battery which is equivalent toa parallel combination of two batteries of emf `V_1` and `V_2` and internal resistances `r_1` and `r_2` respectively, with polrities as shown in figure

Text Solution

Verified by Experts

`(V_(1)r_(2)-V_(2)r_(1))/(r_(1)+r_(2))`, `(r_(1)r_(2))/(r_(1)+r_(2))`
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the emf and internal resistance of a single battery which is equivalent to a combination of three batteries as show in figure.

Find the emf and internal resistance of a single battery which is equivalent to a combination of three batteries as show in figure.

Two batteries of emf epsi_(1) and epsi_(2)(epsi_(2) gt epsi_(1)) and internal resistance r_(1) and r_(2) respectively are connected in parallel as shown in figure.

Two batteries of e.m.f. E_(1) and E_(2) and internal resistance r_(1) and r_(2) are connected in parallel. Determine their equivelent e.m.f.

A resistor R is conneted to a parallel combination of two identical batteries each with emf E and an internal resistance r. The potential drop across the resistance R is.

Two batteries of emf epsilon_(1) and epsilon_(2) (epsilon_(2)gtepsilon_(1) and internal resistances r_(1) and r_(2) respectively are connected in parallel as shown in Fig. 2 (EP).1.

Two batteries of emf epsilon_(1) and epsilon_(2) (epsilon_(2)gtepsilon_(1) and internal resistances r_(1) and r_(2) respectively are connected in parallel as shown in Fig. 2 (EP).1.

Two batteries of emf epsilon_(1) and epsilon_(2) (epsilon_(2)gtepsilon_(1) and internal resistances r_(1) and r_(2) respectively are connected in parallel as shown in Fig. 2 (EP).1.

A battery of emf 2 V and initial resistance 1 Omega is connected across terminals A and B of the circuit shown in figure .