Home
Class 12
PHYSICS
Consider the shown arrangement where eac...

Consider the shown arrangement where each capacitor (without dielectric) has capacitance of 2 muF. However, one of the capacitor has got a dielectric of dielectric constant 2. When the system is in equilibrium, the dielectric is suddenly removed. How much charge would flow along the indicated direction

A

`(10)(3)muC`

B

`(-10)/(3)muC`

C

Zero

D

`( 20)/(3)muC`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

A parallel plate air capacitor has a capacitance C. When it is half filled with a dielectric of dielectric constant 5, the percentage increase in the capacitance will be

A paralle plate air capacitor has capacitance C. Now half of the space is fillel with a dielectric material with dielectric constant K as shown in figure . The new capacitance is C . Then

A parallel plate air capacitor has capacitance C. Half of space between the plates is filled with dielectric of dielectric constant K as shown in figure . The new capacitance is C . Then

A parallel plate condenser has a capacitance 50 muF in air and 110 muF when immersed in an oil. The dielectric constant k of the oil is

A parallel plate capacitor is made of two circular plates separated by a distance 5mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3xx10^4V//m the charge density of the positive plate will be close to:

Two parallel plate capacitors, each of capacitance 40 muF, are connected is series. The space between the plates of one capacitor is filled with a dielectric material of dielectric constant K =4. Find the equivalent capacitacne of the system.

Find an expression for the capacitance of a parallel plate capacitor when a dielectric slab of dielectric constant K and thickness t=(d)/(2) but the same area on the plates is inserted between the the capacitors plate. (d=separation between the plates)

A parallel plate capacitor with air between the plates has a capacitance C. If the distance between the plates is doubled and the space between the plates is filled with a dielectric of dielectric constant 6, then the capacitance will become.

Consider a parallel plate capacitor of 10 muF (micro-farad) with air filled in the gap between the plates. Now one half of the space between the plates is filled with a dielectric of dielectric constant 4 , as shown in the figure. The capacity of the capacitor charges to

A parallel plate capacitor without any dielectric has capacitance C_(0) . A dielectric slab is made up of two dielectric slabs of dielectric constants K and 2K and is of same dimensions as that of capacitor plates and both the parts are of equal dimensions arranged serially as shown. If this dielectric slab is introduced (dielectric K enters first) in between the plates at constant speed, then variation of capacitance with time will be best represented by :