Home
Class 12
CHEMISTRY
2 moles of the same gas are enclosed in ...

2 moles of the same gas are enclosed in two containers A and B at `27^(@)C` and at pressure 2 and 3 atms respectively. The rms velocity .

A

will be same in both the container 'A' and 'B'

B

will be more in container 'B'

C

will be more in container 'A'

D

can't be said as Volume of the container is not mentioned.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the root mean square (rms) velocity of the gas in two containers A and B, we will follow these steps: ### Step 1: Understand the Given Information We have: - 2 moles of the same gas in both containers. - Temperature (T) = 27°C = 300 K (convert to Kelvin by adding 273). - Pressure in container A (P_A) = 2 atm. - Pressure in container B (P_B) = 3 atm. ### Step 2: Use the Formula for RMS Velocity The formula for the root mean square velocity (v_rms) of a gas is given by: \[ v_{rms} = \sqrt{\frac{3RT}{M}} \] where: - R = universal gas constant = 0.0821 L·atm/(K·mol) - T = absolute temperature in Kelvin - M = molar mass of the gas. ### Step 3: Relate RMS Velocity to Pressure We can also express the rms velocity in terms of pressure and volume using the ideal gas law, \( PV = nRT \): \[ v_{rms} = \sqrt{\frac{3PV}{nM}} \] Since n (number of moles) is constant (2 moles) and M (molar mass) is constant for the same gas, we can simplify our calculations. ### Step 4: Analyze the Relationship From the ideal gas law, we know that: \[ PV = nRT \] This implies that for both containers A and B, the product of pressure and volume is constant. Thus, we can express the rms velocity as: \[ v_{rms} \propto \sqrt{P} \] This means that the rms velocity depends on the square root of the pressure when the number of moles and the molar mass are constant. ### Step 5: Compare the RMS Velocities - For container A: \( v_{rms,A} \propto \sqrt{P_A} = \sqrt{2} \) - For container B: \( v_{rms,B} \propto \sqrt{P_B} = \sqrt{3} \) ### Step 6: Conclusion Since \( \sqrt{3} > \sqrt{2} \), we conclude that: - The rms velocity in container B is greater than that in container A. ### Final Answer The rms velocity will be more in container B.
Promotional Banner

Similar Questions

Explore conceptually related problems

At 27^(@)C and 2.0 atm pressure, the density of propene gas is :

At 27^(@)C and 3.0 atm pressure, the density of propene gas is :

At 27^(@)C and 4.0 atm pressure, the density of propene gas is :

At 27^(@)C and 6.0 atm pressure, the density of propene gas is :

At 27^(@)C and 5.0 atm pressure, the density of propene gas is :

At 27^(@)C and 7.0 atm pressure, the density of propene gas is :

At 27^(@)C and 8.0 atm pressure, the density of propene gas is :

One gram of hydrogen and 112 g of nitrogen are enclosed in two separate containers each of volume 5 L and at 27^@C . If the pressure of the hydrogen is 1 atm, then the pressure of nitrogen would be

What is the density of CO_(2) at 27 .^(@)C and 2.5 atm pressure ?

Some ideal monoatomic gas A in an enclosure has a pressure P and the temperature T . Another ideal monoatomic gas B enclosed in a container of the same volume has a pressure of 2P and temperature T/2 . The ratio of the average kinetic energy per molecule of gas A to gas B is