The equivalent conductances of sodium chloride, hydrochloric acid and sodium acetate at infinite dilution are 126.45, 426,16 and 91.0 `ohm^(-1)cm^(2) equiv^(-1)`, respectively, at `25^(@)C` . Calculate the equivalent conductance of acetic acid at infinite dilution.

Answer

To calculate the equivalent conductance of acetic acid (CH₃COOH) at infinite dilution, we can use the following relationship based on the conductance values of sodium chloride (NaCl), hydrochloric acid (HCl), and sodium acetate (CH₃COONa):

### Step-by-Step Solution:

1. **Identify the given values:**
- Equivalent conductance of NaCl (λ∞ NaCl) = 126.45 ohm⁻¹ cm² equiv⁻¹
- Equivalent conductance of HCl (λ∞ HCl) = 426.16 ohm⁻¹ cm² equiv⁻¹
- Equivalent conductance of sodium acetate (λ∞ CH₃COONa) = 91.0 ohm⁻¹ cm² equiv⁻¹

2. **Use the formula to find λ∞ of acetic acid:**
The equivalent conductance of acetic acid at infinite dilution can be calculated using the following equation:
\[ \lambda∞_{CH₃COOH} = \lambda∞_{CH₃COONa} + \lambda∞_{HCl} - \lambda∞_{NaCl} \]

3. **Substitute the values into the equation:**
\[ \lambda∞_{CH₃COOH} = 91.0 + 426.16 - 126.45 \]

4. **Perform the calculations:**
- First, add λ∞ of CH₃COONa and λ∞ of HCl:
\[ 91.0 + 426.16 = 517.16 \]
- Then, subtract λ∞ of NaCl:
\[ 517.16 - 126.45 = 390.71 \]

5. **Final result:**
\[ \lambda∞_{CH₃COOH} = 390.71 \, \text{ohm}^{-1} \text{cm}^2 \text{equiv}^{-1} \]