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Which of the following compounds have mo...

Which of the following compounds have more than one type of hybridisation for carbon?
(i) `HC-=CH`
(ii) `CH_(2)=CH-C-=CH`
(iii) `CH_(3)CH=CHCH_(3)`
(iv) `CH_(3)CH_(2)CH_(2)CH_(3)`

A

(iii)

B

(i)

C

(ii) and (iii)

D

(i) and (iii)

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds have more than one type of hybridization for carbon, we will analyze each compound step by step. ### Step 1: Analyze Compound (i) `HC≡CH` - The structure is H-C≡C-H. - Each carbon in this compound is involved in a triple bond. - For each carbon, there are 2 bonds (one triple bond counts as one bond) and no lone pairs. - Hybridization = Number of bonds + Number of lone pairs = 2 + 0 = 2. - Therefore, both carbons are **sp** hybridized. ### Conclusion for (i): - **Hybridization Types**: Only **sp**. - **More than one type?**: No. --- ### Step 2: Analyze Compound (ii) `CH₂=CH-C≡CH` - The structure is CH₂=CH-C≡C-H. - For the first carbon (CH₂): - Bonds: 2 (double bond with the second carbon) + 0 (no lone pairs) = 2. - Hybridization = 2 → **sp²**. - For the second carbon (CH): - Bonds: 3 (double bond with the first carbon and single bond with the third carbon) + 0 = 3. - Hybridization = 3 → **sp²**. - For the third carbon (C≡C): - Bonds: 2 (triple bond with the fourth carbon) + 0 = 2. - Hybridization = 2 → **sp**. - For the fourth carbon (C): - Bonds: 1 (triple bond with the third carbon) + 0 = 1. - Hybridization = 2 → **sp**. ### Conclusion for (ii): - **Hybridization Types**: **sp²** and **sp**. - **More than one type?**: Yes. --- ### Step 3: Analyze Compound (iii) `CH₃-CH=CH-CH₃` - The structure is CH₃-CH=CH-CH₃. - For the first carbon (CH₃): - Bonds: 4 (single bonds) + 0 = 4. - Hybridization = 4 → **sp³**. - For the second carbon (CH): - Bonds: 3 (double bond with the third carbon) + 0 = 3. - Hybridization = 3 → **sp²**. - For the third carbon (CH): - Bonds: 3 (double bond with the second carbon) + 0 = 3. - Hybridization = 3 → **sp²**. - For the fourth carbon (CH₃): - Bonds: 4 (single bonds) + 0 = 4. - Hybridization = 4 → **sp³**. ### Conclusion for (iii): - **Hybridization Types**: **sp²** and **sp³**. - **More than one type?**: Yes. --- ### Step 4: Analyze Compound (iv) `CH₃-CH₂-CH₂-CH₃` - The structure is CH₃-CH₂-CH₂-CH₃. - All carbons are connected by single bonds. - For each carbon: - Bonds: 4 (single bonds) + 0 = 4. - Hybridization = 4 → **sp³**. ### Conclusion for (iv): - **Hybridization Types**: Only **sp³**. - **More than one type?**: No. --- ### Final Conclusion: The compounds with more than one type of hybridization for carbon are: - **(ii) CH₂=CH-C≡CH** (sp² and sp) - **(iii) CH₃-CH=CH-CH₃** (sp² and sp³) ### Summary: - **Answer**: (ii) and (iii) have more than one type of hybridization. ---
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