Home
Class 12
CHEMISTRY
The E^(Theta) for Cl(2)//Cl^(-) is +1.36...

The `E^(Theta)` for `Cl_(2)//Cl^(-)` is `+1.36` for `I_(2)//I^(-)` is `+0.53, " for " Ag^(+)//Ag` is `+0.79, Na^(+)//Na` is `-2.71` and for `Li^(+)//Li` is `-3.04` Arrange the following ionic spects in decreasing order of reducing strength:
`I^(-), Ag, Cl^(-), Li, Na`

Text Solution

Verified by Experts

The more negative or less positive is the electrode potential, more is the reducing strength of the species. Since the electrode potentials increase in the order: LI (-3.04 .V) < Na (- 2.71 V) <1. (+ 0.53 V) < Ag (+0.79 V) Na >> Ag > cr
Promotional Banner

Similar Questions

Explore conceptually related problems

a. Arrange the following species in decreasing order of their sizes//ionic radii. i. Ar, K^(o+),Cl^(ɵ),S^(2-) and Ca^(2+)

Arrange the following in the decreasing order of their thermal stability of Cl_(2), F_(2), I_(2), Br_(2) .

Arrange the following ions in order of increasing ionic radii. Li^(+), Na^(+), Al^(3+),K^(+),Mg^(2+)

Arrangement the following elements in increasing order of their atomic radii (a) Li, Be, F, N (b) Cl, At, Br, I

Arrange the following ions in order of their decreasing ionic radii. Li^(o+), K^(o+), Mg^(2+), Al^(3+)

Arrange the following in the decreasing order of their boiling points: (i) C_2H_5Br (ii) C_2H_5Cl (iii) C_2H_5I

E^(@) for CL_(2)//Cl^(-)=+1.36,I_(2)//I^(-)=+0.53,Ag^(+)//Ag=+0.79,Na^(+)//Na=-2.71 and Li^(+)//Li=-3.04V . What is the order of decreasing reducing sterngth for these species?

Arrange the following in order of decreasing ionic character M-F,M-Cl,M-Br,M-I.

Arrange the following in order of increasing ionic character : C-H,F-H,Br-H,Na-I, K-F and Li-Cl

Arrange the following : Increasing oxidising power F_(2),Cl_(2),Br_(2),I_(2)