When boron is fused with NaOH, products formed are:

Options

A. `Na_(2)B_(4)O_(7)`and `H_(2)`
B. `Na_(2)BO_(2)`and `H_(2)`
C. `Na_(3)BO_(3)`and `H_(2)`
D. `B_(2)O_(3)`and `H_(2)`

Answer

To solve the question "When boron is fused with NaOH, what products are formed?", we can follow these steps:

### Step 1: Understand the Reaction
When boron (B) is fused with sodium hydroxide (NaOH), a chemical reaction occurs. We need to identify the products of this reaction.

### Step 2: Write the Chemical Equation
The reaction can be represented as:
\[ \text{B} + \text{NaOH} \rightarrow \text{Na}_3\text{BO}_3 + \text{H}_2 \]

### Step 3: Balance the Chemical Equation
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides.

1. **Boron (B)**: There is 1 boron atom on the left and 1 in the product Na3BO3 on the right.
2. **Sodium (Na)**: There are 3 sodium atoms in Na3BO3. Therefore, we need 3 NaOH on the left.
3. **Hydrogen (H)**: Each NaOH contributes 1 hydrogen atom, so 3 NaOH gives 3 hydrogen atoms. Additionally, we need to account for the hydrogen gas (H2) produced. Thus, we need 3 H2 on the right.
4. **Oxygen (O)**: There are 3 oxygen atoms in Na3BO3.

The balanced equation becomes:
\[ 2\text{B} + 6\text{NaOH} \rightarrow 2\text{Na}_3\text{BO}_3 + 3\text{H}_2 \]

### Step 4: Identify the Products
From the balanced equation, we can see that the products formed when boron is fused with NaOH are:
- Sodium borate (Na3BO3)
- Hydrogen gas (H2)

### Conclusion
Thus, the correct answer is that when boron is fused with NaOH, the products formed are sodium borate (Na3BO3) and hydrogen gas (H2).

### Final Answer
The products formed are Na3BO3 and H2.

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