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When excess of SnCl(2) is added to HgCl(...

When excess of `SnCl_(2)` is added to `HgCl_(2)`, the substance formed is

A

`HgCl_(2)`

B

Sn

C

Hg

D

`Cl_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of what substance is formed when excess SnCl₂ is added to HgCl₂, we can follow these steps: ### Step 1: Identify the Reactants We start with two reactants: - **HgCl₂** (Mercury(II) chloride) - **SnCl₂** (Tin(II) chloride) ### Step 2: Write the Reaction When SnCl₂ is added to HgCl₂, a reaction occurs. The SnCl₂ can reduce HgCl₂. The initial reaction can be written as: \[ \text{HgCl}_2 + \text{SnCl}_2 \rightarrow \text{Hg}_2\text{Cl}_2 + \text{SnCl}_4 \] ### Step 3: Determine Oxidation States Next, we analyze the oxidation states: - In HgCl₂, mercury (Hg) is in the +2 oxidation state. - In SnCl₂, tin (Sn) is in the +2 oxidation state. - In Hg₂Cl₂, mercury (Hg) is in the +1 oxidation state. ### Step 4: Identify the Reduction Process Since SnCl₂ is in excess, it can further react with the formed Hg₂Cl₂: \[ \text{Hg}_2\text{Cl}_2 + 2\text{SnCl}_2 \rightarrow 2\text{Hg} + 2\text{SnCl}_4 \] In this step, the mercury in Hg₂Cl₂ is reduced from +1 to 0 (elemental mercury). ### Step 5: Final Product The final product of the reaction is elemental mercury (Hg), which is a gray precipitate. ### Conclusion Thus, when excess SnCl₂ is added to HgCl₂, the substance formed is elemental mercury (Hg). ### Answer The correct answer is **Hg** (elemental mercury). ---
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