Both `Cr_(2)O_(7)^(2-)` and `MnO_(4)^(-)` solutions can be used to titrate `Fe^(2+)` in acidic medium. Suppose you have (0.1 M solution of each). For a given sample of `Fe^(2+)` solution. If a given titration requires -7.5 mL of 0.1 m `Cr_(2)O_(7)^(2-)` o solution, how many mL of 0.1 M `MnO_(4)`, would have been if it had been used instead. 

Explanation

To solve the problem of determining how many mL of 0.1 M `MnO4^-` would be required to titrate the same amount of `Fe^(2+)` as 7.5 mL of 0.1 M `Cr2O7^(2-)`, we will follow these steps:

### Step 1: Understand the Reaction
In acidic medium:
- `Cr2O7^(2-)` is reduced from Cr(+6) to Cr(+3).
- `MnO4^-` is reduced from Mn(+7) to Mn(+2).
- `Fe^(2+)` is oxidized to `Fe^(3+)`.

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